9=1/b^2

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Solution for 9=1/b^2 equation: 


D( b )

b^2 = 0

b^2 = 0

b^2 = 0

1*b^2 = 0 // : 1

b^2 = 0

b = 0

b in (-oo:0) U (0:+oo)

9 = 1/(b^2) // - 1/(b^2)

9-(1/(b^2)) = 0

9-b^-2 = 0

-1*b^-2 = -9 // : -1

b^-2 = 9

-2 < 0

1/(b^2) = 9 // * b^2

1 = 9*b^2 // : 9

1/9 = b^2

b^2 = 1/9 // ^ 1/2

abs(b) = 1/3

b = 1/3 or b = -1/3

b in { 1/3, -1/3 }

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